Aabbcc X Aabbcc

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Aabbcc X Aabbcc

een AaBbCc x AaBBCC, what is the probability that the offspring is AABbCc or AABBCC?
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NOTICE THE OR (that means it's addition) Okay so do it by letter. The odds of Aa and Aa making AA or AA are 1/4 for each (so that's two 1/4's). The odds of Bb and BB making Bb or BB are 1/2 for the first and 1/2 for the second (two 1/2's). The odds of Cc and CC making Cc or CC are 1/2 for the first and 1/2 for the second (again, two 1/2's). So now you multiply all the letter probabilities for the first thing (which was AABbCc- so you do (1/4)(1/2)(1/2)) and that gets you 1/16. Do the same for the second (AABBCC- (1/4)(1/2)(1/2)) and you get 1/16 also. So now you add 1/16 + 1/16 and you get 2/16 which simplifies to 1/8 (final answer). #EvenMoreComplicatedRuleOfAddition

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