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You Have Sampled A Population In Which You Know That The Percentage Of The Homozygous Recessive

genotype (aa) is 36%. Using that 36%, calculate the frequency of the genotypes "AA" and "Aa.
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The frequency of aa is 36%, which means that q2 = 0.36. If q2 = 0.36, then q = 0.6. Since q = 0.6, and p + q = 1, then p = 0.4. The frequency of AA is equal to p2, and the frequency of Aa is equal to 2pq. So, the frequency of AA is 16% (i.e. p2 is 0.4 x 0.4 = 0.16) and Aa is 48% (2pq = 2 x 0.4 x 0.6 = 0.48).

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