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At 298 K, The Henry'S Law Constant For Oxygen Is 0.00130 M/Atm. Air Is 21.0% Oxygen.

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1) At 298 K, what is the solubility of oxygen in water exposed to air at 1.00 atm? 0.00130 M/atm 0.21 1 atm = 0.000273 mole / L 2) At 298 K, what is the solubility of oxygen in water exposed to air at 0.894 atm? 0.00130 M/atm 0.21 0.894 atm = 0.000244 mole / L 3) If atmospheric pressure suddenly changes from 1.00 atm to 0.894 atm at 298 K, how much oxygen will be released from 3.60 L of water in an unsealed container? .0000273 - .000244 = .000029 x 3.6 L = 0.0001044

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